causes (2+1)*TimeOutSpan delay after end of data in UART stream number of currently received data bytes Int TimeOutCnt = _tickCount + _receiveTimeout counts delay in TimeOutSpan-s after end of data to break receive / In other hand, if any data has received, first no-data cycle / If no any message received during ReceiveTimeout property, / data received using BaseStream.ReadTimeout = TimeOutSpan (2 ms). / The routine works in "pseudo-blocking" mode. / It works likes socket-recv routine (explanation in body). / Or throws TimeoutException if no any data arrived during ReceiveTimeout. / It Receives up to maxLen number bytes of data, / It uses SerialPort.BaseStream rather SerialPort functionality. or short timeout (theoretical 6 ms) in UART data flow.it receives data either until maxLen bytes.In other hand, when any data has received,.in one hand it has timeout for no any data and throws TimeoutException.
Has name and works like "well known" socket's recv().
SerialPort.BaseStream-source for deep understanding. You can see source code: SerialPort-source and I spent a lot of time to use SerialPort class and has concluded to use SerialPort.BaseStream class instead. Show all the incoming data in the port's buffer Private void port_DataReceived(object sender, Enter an application loop to keep this thread alive SerialDataReceivedEventHandler(port_DataReceived) Attach a method to be called when there Private SerialPort port = new SerialPort("COM1", Create the serial port with basic settings It even covers the pin assignments on the port itself. NET to read and write data, determine what serial ports are available on your machine, and how to send files. This article explains how to use the SerialPort class in.
SerialPort (RS-232 Serial COM Port) in C#.
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